A simple pendulum bob has a mass `''m''` and length `''L''`. The bob is drawn aside such that the string is horizontal and then it is released. The velocity of the bob while it crosses the equilibrium position is

Options

A. `sqrt(g L)`
B. `sqrt(2g L)`
C. `sqrt(5 gL)`
D. `sqrt(3 gL)`

Answer

B

Explanation

`"Loss of P.E = Gain in K.E"` , `mgL = (1)/(2) M V^(2)`