An elevator can carry a maximum load of ...

An elevator can carry a maximum load of `1800 kg` (elevator + passengers) is moving up with a constant speed of `2 ms^(-1)`. The friction force opposite the motion is `4000 N`.What is minimum power delivered by the motor to the elevator?

`59`

`8`

`22`

`20`

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The correct Answer is:

`F = mg + "frictional force"`, `P = vec(F).vec(v)`

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