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A simple pendulum is oscillating with an...

A simple pendulum is oscillating with angular displacement `90^(@)` For what angle with vertical the acceleration of bob direction horizontal?

A

`sin^(-1)((1)/(3))`

B

`cos^(-1) ((1)/(3))`

C

`sin^(-1)((1)/(sqrt(3)))`

D

`cos^(-1)((1)/(sqrt(3)))`

Text Solution

Verified by Experts

The correct Answer is:
D
`tan theta = (a_(c ))/(a_(t)) = (v^(2)//r)/(g sin theta)`
but `v^(2) = 2 gh`, `h = r cos theta`
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