A steel wire can withstand a load up to `2940N`. A load of `150 kg` is suspended from a rigid support. The maximum angle through which the wire can be displaced from the mean position, so that the wire dose not break when the load passs through the position of equilibrium, is

Options

A. `30^(@)`
B. `60^(@)`
C. `80^(@)`
D. `85^(@)`

Answer

B

Explanation

While crossing the equilibrium position
`T = mg+(m v^(2))/(r ) = mg+(m)/(l)[2gl(1- cos theta)]`
`= mg+2mg-2mg cos theta = mg[3-2 cos theta]`