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A stone of mass 6 kg is revolved in a v...

A stone of mass `6 kg` is revolved in a vertical circle of diameter `6m`., such that its speed is minimum at a point. If the `K.E` at the same point is `250 J`, then minimum `PE` at that point is

A

`200 J`

B

`150 J`

C

`100 J`

D

`450 J`

Text Solution

Verified by Experts

The correct Answer is:
A
`T.E_("bottom") = T.E_("given point")(1)/(2)m(sqrt(5 gr))^(2) = P.E+K.E`
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