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A block of mass 1 kg moving with a speed...

A block of mass `1 kg` moving with a speed of `4 ms^(-1)`, collides with another block of mass `2 kg` which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body is

A

`2 ms^(-1)`

B

`1 ms^(-1)`

C

`1.5 ms^(-1)`

D

`0.5 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`m_(1)u_(1)+m_(2)u_(2) = m_(1)v_(1)+m_(2)v_(2)`
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