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After emission of one alpha particle fol...

After emission of one `alpha` particle followed by one `beta`-particle from `""_(92)^(238)X`, the number of neutrons in the atom will be

A

`140`

B

`142`

C

`144`

D

`146`

Text Solution

Verified by Experts

The correct Answer is:
B
`._(92)U^(238)rarr._(92)x^(234)+._(2)He^(4)+._(-1)e^(0)`
no of neutrons `=234 - 92 = 142`
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