No. of uranium 235 nuclei required to un...

No. of uranium `235` nuclei required to undergo fission to give `9xx10^(13)` joule of energy is

`2.8125xx10^(24)`

`28.125xx10^(24)`

`281.25xx10^(24)`

`28215xx10^(24)`

Text Solution

Verified by Experts

The correct Answer is:

`200 MeV rarr1"fission"`
`9xx10^(13) J rarr?`
Number of fission `=(9xx10^(3))/(200xx10^(6)xx1.6xx10^(-19))`

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