The amount of energy released in the fusion of two `._(1)H^(2)` to form a `._(2)He^(4)` nucleus will be {Binding energy per nucleon of `._(1)He^(2)=1.1 MeV` Binding energy per nucleon of `._(2)He^(4)=7 MeV`]

Options

A. `8.1 MeV`
B. `5.9 MeV`
C. `23.6 MeV`
D. `2 MeV`

Answer

C

Explanation

`._(1)H^(2)+._(1)H^(2)rarr._(2)He^(4)+Q`
`E=B.E.` of product `-B.E` of reactants
`=4(7)-4(1.1)=23.6 MeV`