Home
Class 12
PHYSICS
.^22 Ne nucleus after absorbing energy d...

`.^22 Ne` nucleus after absorbing energy decays into two `alpha-`particles and an unknown nucleus. The unknown nucleus is.

A

Carbon

B

Nitrogen

C

Boron

D

oxygen

Text Solution

Verified by Experts

The correct Answer is:
A
`._(10)^(22)Ne rarr2._(2)He^(4)+._(6)c^(12)`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    NARAYNA|Exercise Level-III|38 Videos

  • NUCLEAR PHYSICS

    NARAYNA|Exercise Level-V questions(Single answer type questions)|12 Videos

  • NUCLEAR PHYSICS

    NARAYNA|Exercise Level-1 (C.W)|21 Videos

  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise EXERCISE - 4|20 Videos

  • NUCLEI

    NARAYNA|Exercise ASSERTION & REASON|5 Videos

Similar Questions

Explore conceptually related problems

Ne nucleus , the after absorbing energy , decays into two a - particle and an unknown nucleus . The unknown nucleus is

.^(22)Ne nucleus after absorting energy, decays into two alpha-particles and an unknown nucleus. The nucleus is:

A nucleus ._n^ m X emits one alpha- particle and two beta- particles. The resulting nucleus is

An unknown stable nuclide after absorbing a neutron emits an electron, and the new nuclide splits spontaneously into two alpha particles. The unknown nuclide is :

A nucleus ._n X^m emits one alpha and one beta particles. The resulting nucleus is.

When a nucleus decays by emitting a beta -particle, the daughter nucleus has one more

In Rutherford experiment alpha – particles are scattered by nucleus having change 100 e^(-) Initial kinetic energy of alpha - particles is 6 MeV . The size of the nucleus is

Statement-1: Distance of closest approach of alpha particle to the nucleus is always greater than the size of the nucleus. Statement-2: Strong nuclear repulsion does not allow alpha particle to reach the surface of nucleus.