The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

Options

A. `M=m_("proton")+m_("electron")`
B. `M=m_("proton")+m_("electron")-(B)/(c^(2))(B=13.6 eV)`
C. `M` is not related to the mass of the hydrogen atom.
D. `M=m_("proton")+m_("electron")`
`-(|V|)/(c^(2))({:(|V|="magnitude of hte potentail energy"),("of electron in the"H-"atom"):})`

Answer

B

Explanation

`M lt m_(p)+m_(e )` due to release of atomic binding energy `(13.6 eV)`
during H-atom creation.