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Find the decay constant of .^(55)Co radi...

Find the decay constant of `.^(55)Co` radio nuclide if its activity is known to decrease `4%` per hour. The decay product is non-radioactive.

A

`1.1xx10^(-5)s^(-1)`

B

`2.2xx10^(-5)s^(-1)`

C

`3.3xx10^(-5)s^(-1)`

D

`4.4xx10^(-5)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Activity `A=lambda N_(0)e^(-lambda t)`
Since activity decreases at `4.0%` per hour, activity of `.^(55)Co` radio nuclide at `t=1 hr`.
`A=A_(0)-eta A_(0)` where `eta=0.04`
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