For a certain radioactive substance, it is observed that after `4h`, only `6.25%` of the original sample is left undeacyed. It follows that.

Options

A. the half life of the sample is `1` hour
B. the mean life to the sample is `1//ln 2` hour
C. the decay constant of the sample is `ln2 hour^(-1)`
D. after a further `4` hours, the amount of the substance left over would be only `0.39%` of the original amount

Answer

A, B, C, D

Explanation

6.25% means, `N=(N_(0))/(16),` that means, `t=4T_(1//2)`