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Assume that the mass of nucleus is given...

Assume that the mass of nucleus is given by `M=Amp` where `A` is the mass number and `mp=1.00727 u`. The density of the matter in the nucleus is about `yxx10^(17)kg//m^(3)`. Then `y` is _______
(Take `R_(0)=1.5Fm`)

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The correct Answer is:
1
`d(m)/(V)=(Axx1.000727u)/((4)/(3)pi(R_(0)A^(1//3))^(3))=yxx10^(17)`
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