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There are two radio-active nuclei `A` and `B`. `A` in an alfa-emitter while `B` is a beta-emitter, Their disintegration constant are in the ratio of `1:4`. The ratio of number of nuclei of `A` and `B` at any time `'t'` such that probabilities of getting number of alpha and beta particles are same at the instant is `y:1`. Then `y`______is

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The correct Answer is:
D
`N_(1)lambda_(1)=N_(2)lambda_(2)rArr (N_(A))/(N_(B))=(lambda_(2))/(lambda_(1))=(4)/(1)`
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