Consider a nuclear reaction `A+B rarr C`. A nucleus `A` moving with kinetic energy of `5 MeV` collides with a nucleus `B` moving with kinetic energy of `3MeV` and forms a nucleus `C` in exicted state. Find the kinetic energy of nucleus `C` just after its fromation if it is formed in a state with excitation energy `10 MeV`. Take masses of nuclei of `A,B` and `C ` as `25.0,10.0,34.995 amu`, respectively.
(1amu=`930 MeV//c^(2))`.

Answer

B

Explanation

`m_(A)C^(2)+K_(A)+m_(B)C^(2)+k_(B)=m_(C)C^(2)+k_(c)+` exciation energy.
`(m_(A)+m_(B)-m_(c))c^(2)+k_(A)+k_(B)-k_(C)=` excitation energy `:. k_(C)=2MeV`