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Radon 220 decays to Bismuth 212 by the f...

Radon `220` decays to Bismuth `212` by the following series of decay
`{:(._(86)Rnrarr_(84),Po^(216)+_(2),He^(4),,T_(1//2)=55s,),(._(84)Po^(216)rarr_(82),Pb^(212)+_(2),He^(4),,T_(1//2)=0.016s,),(._(82)Pb^(212)rarr_(83),Bi^(212)+_(-1),e^(0),,T_(1//2)=10..6s,):}`
If certain mass of randon is allowed to decay in certain container, after five minutes element with greatest and least mass will respectively be

A

Randon, bismuth

B

Polonium, lead

C

Lead, bismuth

D

Bismuth, lead

Text Solution

Verified by Experts

The correct Answer is:
C

small `T_(1//2)` indicates that more such reactions take place.
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