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A stationary nucleus of mass 24 amu emit...

A stationary nucleus of mass `24` amu emits a gamma photon. The energy of the emitted photon is `7 MeV`. The recoil energy of the nucleus is

A

`2.2 keV`

B

`1.1 keV`

C

`3.1 keV`

D

`22 keV`

Text Solution

Verified by Experts

The correct Answer is:
B
momentum of a photon, `P=(h)/(lambda)=(E)/(C)`.
Apply law of conservation of linear momentum and get the recoil energy of nucleus and `E=(p^(2))/(2m)`.
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