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At t=0, number of radioactive nuclei of ...

At `t=0`, number of radioactive nuclei of a radioactive substance are `x` and its radioactivity is `y`. Half-life of radioactive substance is `T`. Then,

A

`(x)/(y)` is constant throughout

B

`(x)/(y) gt T`

C

Value of `xy` remains half after one half-life

D

Value of `xy` becomes one fourth after one half-life

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`x=N` and`y= lambdaN, (x)/(y)=(1)/(lambda)=(T)/(0.693)`
`xy=lambda N^(2)`, so after one half-life it's value becomes `1//4^(th)` of its value.
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