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A beam of alpha paricles is incident on a target of lead. A particular alpha paticles comes in 'head- on' to a particular lead nucleus and stops `6.50 xx 10^(-14)` m away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has `82` protons, remains at rest. The mass of alpha particle is `6.64 xx 10^(-27)kg`
What was the initial speed of the alpha particle?

A

`132xx10^(2)ms^(-1)`

B

`1.32xx10^(7) ms^(-1)`

C

`13.2xx10^(2) ms^(-1)`

D

`0.31xx10^(7) ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`K=(1)/(2)mv^(2)`
`:. V=sqrt((2K)/(m))=sqrt((2(5.82xx10^(-13)J))/(6.64xx10^(-27)kg))=1.32xx10^(7)ms^(-1)`
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