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The isotope .(92)U^(238) successively un...

The isotope `._(92)U^(238)` successively undergoes eight `alpha`-decays and six `beta`-decays. The resulting isotope is found to be `._(92-5y)X^(238-4x)`. Find the value of ratio `x//y`.

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The correct Answer is:
4
`._(92)U^(238)overset( 8alpha+6 beta)rarr_(82)Pb^(206)`
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