Home
Class 12
PHYSICS
The nuclide which disintergrates by emit...

The nuclide which disintergrates by emitting a `beta`-particles to form `._(7)^(14)N` contains

A

8 neutrons

B

10 neutrons

C

7 neutrons

D

6 neutrons

Text Solution

Verified by Experts

The correct Answer is:
A
`._(7)N^(14)rarr_(6)X^(14)+_(-1)e^(0)`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    NARAYNA|Exercise LEVEL-II-(H.W)|9 Videos

  • NUCLEAR PHYSICS

    NARAYNA|Exercise Previous JEE questions|21 Videos

  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise EXERCISE - 4|20 Videos

  • NUCLEI

    NARAYNA|Exercise ASSERTION & REASON|5 Videos

Similar Questions

Explore conceptually related problems

1 mol of ._(7)^(14)N^(-3) ions contains:

Which emits beta -particles ?

Th^(234) disintergrates and emits 6beta- and 7alpha- particles to form a stable product. Find the atomic number and mass number of the stable product and also identify the element.

._(92)^(239)U decays emitting a beta- particle producing neptunium nucleus. Which futher decays emitting a beta- particle and the daughter product is plutonium (Pu). The grand daughter product can be expressed as:

When ._(92)U^(238) decauys it emits an a-particle. The new nuclide in turn emits a beta-particele to give another nuclide X. The mass number and atomic number of X are. Respectively .

._(92)^(235)U decays with emission of alpha and beta - particles to form ultimately ._(82)^(207)Pb . How many alpha and beta -particles are emitted per atom of Pb produced?

The atomic number (A) and mass number (M) of the nuclide formed where three alpha (alpha) and two (beta) particles are emitted from ._(92)^(238)U

A nuclide at rest emits an alpha-particle. In this process: