The circuit shown in figure (1) Contains two diodes each with a forward resistance of `50 ohm` and with infinite reverse resistance. If the battery voltage is `6 V`, the current through the `100 ohm` resistance is.
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Options

A. `0.01 A`
B. `0.02 A`
C. `0.03 A`
D. `0.04A`

Answer

B

Explanation

As per given circuit, diode `D_(1)` is forward biased and offers a resistance of `50 ohm`, Diode `D_(2)` is reverse biased and as its corresponding resistance is infinite, no current flows through it. Thus the equivalent circuit is as shown in figure (2). As all the three resistance are in series, the current through then is
`I=(6V)/((50+150+100)Omega)`
`= (6)/(300) A = 0.02 A`.
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