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The constant alpha of a transistor is 0....

The constant `alpha` of a transistor is `0.9` What would be the change in the collector current corresponding to a change of `4mA` in the base current in a common emitter arrangement ?

A

`30mA`

B

`63mA`

C

`36mA`

D

`3.6mA`

Text Solution

Verified by Experts

The correct Answer is:
C
`beta=(alpha)/(1-alpha)` But `beta =((delta I_(C))/(delta I_(B)))_(V_(CE))`
`rArr delta I_(C) = beta.delta I_(B)=9 xx 4 mA`.
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