In a single state transistor amplifier, when the signal changes by `0.02 V` the base current by `10 mu A` and collector current by `1 mA`. If collector load `R_(C) = 2k Omega` and `R_(L) = 10 k Omega`, Calculate :
(i) Current Gain
(ii) Input Impedance,
(iii) Effective `AC` load,
(iv) Voltage gain and
(v) Power gain.

Options

A. `50,2k Omega,1.66 k Omega,83,8300`
B. `100,1 k Omega,1.66 Omega,83,8300`
C. `100, 2k Omega,1.66 k Omega,83,830`
D. `100,2 k Omega,1.66 k Omega,83.8300`

Answer

D

Explanation

(i) Current Gain `beta -(delta i_(c))/(delta i_(b))`
(ii) Input impedance `R_(i)=(delta V_(BE))/(delta i_(b))`
(iii) Effective (ac) load `R_(AC)=(R_(C)R_(L))/(R_(C)+R_(L))`
(iv) Voltage gain `A_(v)=beta xx (R_(AC))/(R_(i n))`
(v) Power gain, `A_(p) = A_(v) xx beta`.