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`n` conducting wires of same dimensions but having resistivities 1,2,3,….n are connected is series. The equivalent resistivity of the combination is

A

`(n(n+1))/(2)`

B

`(n+1)/(2)`

C

`(n+1)/(2n)`

D

`(2n)/(n+1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`R=R_(1)+R_(2)+…R_(n)`
`(rho(nl))/(A)=l(l)/(A)+2(l)/(A)+….+n(l)/(A)`
`rhon=1+2+3+…+n`
`rhon=(n(n+1))/(2)=(n+1)/(2)`
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