A lamp of 600W-240V is connected to 220 V mains. Its resistance is

Options

A. `96Omega`
B. `84Omega`
C. `90Omega`
D. `64Omega`

Explanation

To find the resistance of a lamp rated at 600W and 240V when connected to a 220V mains supply, we can use the formula relating power, voltage, and resistance.

### Step-by-Step Solution:

1. **Identify the given values:**
- Power (P) = 600 W
- Voltage (V) = 240 V (this is the rated voltage of the lamp)

2. **Use the formula for power:**
The power (P) of an electrical device can be expressed in terms of voltage (V) and resistance (R) as:
\[ P = \frac{V^2}{R} \]

3. **Rearrange the formula to solve for resistance (R):**
\[ R = \frac{V^2}{P} \]

4. **Substitute the known values into the formula:**
\[ R = \frac{(240)^2}{600} \]

5. **Calculate \(240^2\):**
\[ 240^2 = 57600 \]

6. **Now substitute this value back into the equation:**
\[ R = \frac{57600}{600} \]

7. **Perform the division:**
\[ R = 96 \, \Omega \]

8. **Conclusion:**
The resistance of the lamp is \(96 \, \Omega\).