Home
Class 12
PHYSICS
An electron of mass 9xx10^(-31)kg moves ...

An electron of mass `9xx10^(-31)kg` moves around a nucleus in a circular orbit of radius `2A^(@)` under the action of centripetal force 3.2N. Then the equivalent electric current is

A

`(32)/(3pi)`

B

`(3pi)/(32)`

C

`(16)/(3pi)`

D

`(3pi)/(16)`

Text Solution

Verified by Experts

The correct Answer is:
A
`i=(q)/(t)=(qv)/(2pir)`
`[becauseF=(mv^(2))/(r)]`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 3|46 Videos

  • CURRENT ELECTRICITY

    NARAYNA|Exercise NCERT Based Questions|13 Videos

  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 2 C.W|59 Videos

  • COMMUNICATION SYSTEM

    NARAYNA|Exercise Level-II(H.W)|25 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos

Similar Questions

Explore conceptually related problems

Anelectron of mass m, moves around the nucleus in a circular orbit of radius r under the action of ccentripetal force F . The equivalent electric current is

Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

Knowledge Check

  • A proton of mass 1.6 xx 10^(-27)kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4 xx 10^(-13) N . then the frequency of revolution of the proton is about

    A
    `0.08 xx 10^(8)` cycles per sec
    B
    `4 xx 10^(8)` cycles per sec
    C
    `8 xx 10^(8)` cycles per sec
    D
    `12 xx 10^(8)` cycles per sec

  • A proton of mass 1.6times10^-27 kg goes round in a circular orbit of radius 0.12 m under a certripetal force of 6 times 10^-14 N. then the frequency of revolution of the proton is about

    A
    `1.25 times 10^6` cycles per second
    B
    `2.50 times 10^6` cycles per second
    C
    `3.75 times 10^6` cycles per second
    D
    `5.00 times 10^6` cycles per second

  • An electron has a mass of 9.1 xx 10^(-31)kg . It revolves round the nucleus in a circular orbit of radius 0.529 xx 10^(-10) metre at a speed of 2.2 xx 10^(6) m//s . The magnitude of its linear momentum in this motion is

    A
    `1.1 xx 10^(-34) kg-m//s`
    B
    `2.0 xx 10^(-24) kg-m//s`
    C
    `4.0 xx 10^(-24) kg-m//s`
    D
    `4.0 xx 10^(-31) kg-m//s`

    • Similar Questions

    Explore conceptually related problems

    Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

    In Bohr model of hydrogen atom , the electron revolves around the nucleus in a circular orbit of radius 5.1 xx 10^(-11)m at a frequency of 6.8 xx 10^(15) revolutions per second. Find the equivalent current at may point on the orbit of the electron

    If an electron revolves around a nucleus in a circular orbit of radius R with frequency n, then the magnetic field produced at the centre of the nucleus will be

    If an electron is moving around a nucleus of charge 3theta in a circular orbit of radius 10^(-10) m,then calculate the initial frequency of light emitted by the electron.

    The angular momentum of the electron moving around the nucleus in a circular orbit of radius r is given by

    Home
    Profile