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Four resistances 10 Omega, 5 Omega, 7 Om...

Four resistances `10 Omega, 5 Omega, 7 Omega` and `3 Omega` are connected so that they form the sides of a rectangle `AB, BC, CD` and `DA` respectively. Another resistance of `10 Omega` is connected across the diagonal `AC`. The equivalent resistance between `A` and `B` is

A

`2Omega`

B

`5Omega`

C

`7Omega`

D

`10Omega`

Text Solution

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The correct Answer is:
B
combination of resistors
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