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When a resistor of 11 Omega is connected...

When a resistor of `11 Omega` is connected in series with an electric cell, the current following in it is `0.5 A`. Instead, when a resistor of `5 Omega` is connected to the same electric cell in series, the current increases by `0.4 A` The internal resistance of the cell is

A

`1.5Omega`

B

`2Omega`

C

`2.5Omega`

D

`6Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=i(R+r)`
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