A 5V battery with internal resistance `2Omega` and a 2V battery with internal resistance`1Omega` are connected to a `10Omega` resistor as shown in the figure.

The current in the `10Omega` resistor is

Options

A. `0.27A` `P_(2)` to `P_(1)`
B. 0.03 A `P_(1)` to `P_(2)`
C. 0.03 A `P_(2)` to `P_(1)`
D. 0.27 A `P_(1)` to `P_(2)`

Answer

C

Explanation

`(X)/(R)=(l)/(100-l)`