The length of a wire of a potentiometer is 100 cm, and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is `0.5 Omega`. If the balance point is obtained at I = 30 cm from the positive end, the e.m.f. of the battery is .
where i is the current in the potentiometer wire.

Options

A. `(30E)/(100.5)`
B. `(30E)/(100-0.5)`
C. `(30E)/(100)`
D. `(100E)/(30)`

Answer

C

Explanation

`Valphal,(E^('))/(E)=(30)/(100)`