A rigid container with thermally insulated walls contains a coil of resistance `100Omega`, carrying current 1A. Change in internal energy after 5 min will be

Options

A. zero
B. 10kJ
C. 20kJ
D. 30kJ

Explanation

To find the change in internal energy of the rigid container with a coil of resistance carrying current, we can use the formula for electrical energy converted into heat (internal energy) in a resistor. The formula is:

\[ \Delta U = I^2 R t \]

Where:
- \(\Delta U\) is the change in internal energy,
- \(I\) is the current (in Amperes),
- \(R\) is the resistance (in Ohms),
- \(t\) is the time (in seconds).

### Step-by-Step Solution:

1. **Identify the given values:**
- Resistance \(R = 100 \, \Omega\)
- Current \(I = 1 \, A\)
- Time \(t = 5 \, \text{minutes} = 5 \times 60 \, \text{seconds} = 300 \, \text{seconds}\)

2. **Substitute the values into the formula:**
\[ \Delta U = (1 \, A)^2 \times (100 \, \Omega) \times (300 \, s) \]

3. **Calculate \(I^2\):**
\[ I^2 = 1^2 = 1 \, A^2 \]

4. **Calculate the product:**
\[ \Delta U = 1 \, A^2 \times 100 \, \Omega \times 300 \, s \]
\[ \Delta U = 100 \times 300 \, J \]

5. **Calculate the final value:**
\[ \Delta U = 30000 \, J \]

### Conclusion:
The change in internal energy after 5 minutes is \(30000 \, J\).