In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. `1(cal)/(s)`
B. `2(cal)/(s)`
C. `3(cal)/(s)`
D. `4(cal)/(s)`

Answer

B

Explanation

Since, resistance in upper branch of the circuit is twice the resistance in lower branch. Hence, current there will be half.
Now `P_(4)=((1)/(2))^(4)(4)`
`P_(2)=(i)^(2)(5)`
`=(10)/(5)=2(cal)/(s)`