In the circuit shown in the figure, the current through

Options

A. the `3Omega` resistor is 0.50 A
B. the `3Omega` resistor is `0.25A`
C. The `4Omega` resistor is 0.50 A
D. the `4Omega` resistor is 0.25A

Answer

D

Explanation

Net resistance of the circuit is `Omega`
`therefore` current drawn fromm the battery
`i=(9)/(9)=1A=` current through `3Omega` resistor Potential difference between A and B is
`V_(A)-V_(B)=9-1(3+2)=4V=8i_(1)`
`i_(1)=0.5A`
`thereforei_(2)=1-i_(1)=0.5A`
similarity potential difference between C and D
`V_(C)-V_(D)=(V_(A)-V_(B))-i_(2)(2+2)`
`=4-4i_(2)=4-4(0.5)=2V=8i_(3)`
`i_(3)=0.25A`
Therefore `i_(4)-i_(2)-i_(3)=0.5-0.25`
`i_(2)=0.25A`