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A moving coil galvanometer of resistance...

A moving coil galvanometer of resistance `100Omega` is used as an ammeter using a resistance `0.1 Omega`. The maximum diflection current in the galvanometer is `100 muA`. Find the minimum current in the circuit so that the ammeter shows maximum deflection

A

`100.1mA`

B

`1000.1mA`

C

`10.01mA`

D

`1.01mA`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(ab)=i_(g),G=(i-i_(g))Sbecausei=(1+(G)/(S))i_(g)`
Substituting the values we get
`i=100,imA`
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