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Two bar magnets placed together in a vib...

Two bar magnets placed together in a vibration magnetometer take `3` seconds for `1` vibration. If one magnet is reversed, the comnination takes `4` seconds for `1` vibration. Find the ration of their magnetic moments.

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Given that, `T_(1)=3s` and `T_(2)=4s`
`(M_(1))/(M_(2))=(T_(2)^(2)+T_(1)^(2))/(T_(2)^(2)-T_(1)^(2))=(4^(2)+3^(2))/(4^(2)-3^(2))=(16+9)/(16-9)=(25)/(7)or(M_(1))/(M_(2))=3.57`
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