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Two bar magnets are placed in vibration ...

Two bar magnets are placed in vibration magnetometer and allowed to vibrate. They make `20` oscillations per minute when their similar pole are on the same side, while they make `15` osicillations per minute when their opposite poles lie on the same side. The ratio of their magnetic moments is

A

`7:25`

B

`25:7`

C

`25:16`

D

`16:25`

Text Solution

Verified by Experts

The correct Answer is:
C

`n = (1)/(2pi)sqrt((mB_(H))/(I))`
`20 = 2pisqrt(((M_(1) + M_(2))B_(H))/(2I))`
`= 15 = 2pi 20 = 2pisqrt(((M_(1) - M_(2))B_(H))/(2I))`
`(4)/(3) = sqrt((M_(1) + M_(2))/(M_(1) - M_(2))`
Soving `(M_(1))/(M_(2)) = (25)/(7)`
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