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The relation between mu and H for a spec...

The relation between `mu` and `H` for a specimen of iron is `mu=[(0.4)/(H)+12xx10^(-4)]henry//metre`.
The value of `H` which produces flux density of `1` tesla will be

A

`250A//m`

B

`500A//m`

C

`750A//m`

D

`10^(3)A//m`

Text Solution

Verified by Experts

The correct Answer is:
B
`B = muH`
`B = [(0.4)/(H) + 12x10^(-4)]H`
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