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A magnet makes 10 oscilllations per minu...

A magnet makes `10` oscilllations per minute at a place where the angle of dip is `45^(@)` and the total intensity is `0.4` gauss. The number of oscillations made per sec by the same magnet at another place where the angle of dip is `60^(@)` and the total intensity `0.5` gauss is approximately.

A

`6Hz`

B

`(1)/(1.6xx6)Hz`

C

`6xx1.06Hz`

D

`(1)/(6)Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
`Tprop(1)/(sqrtB),n propsqrtB` and `(n_(1)^(2))/(n_(2)^(2))=(B_(1) cos theta_(1))/(B_(2) cos theta_(2))`
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