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A magnetic needle pivoted through its ce...

A magnetic needle pivoted through its centre of mass and is free to rotate in a plane containing uniform magnetic field `200xx10^(-4)T`. When it is displaced slightly from the equilibrium it makes `2` oscillations per second. If the moment of inertia of the needle about the axis of oxcillation is `0.75xx10^-5)kg m^(2)` , the magnetic moment of the needle is

A

`0.06J//T`

B

`0.03 J//T`

C

`0.12 J//T`

D

`0.6 J//T`

Text Solution

Verified by Experts

The correct Answer is:
A
`f=(1)/(2pi)sqrt((MB)/(I))`
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