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In YDSE, having slits of equal width, le...

In YDSE, having slits of equal width, let `beta` be the fringe width and `I_(0)` be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

A

`I_(0)cos((x)/(beta))`

B

`I_(0)cos^(2)((x)/(beta))`

C

`I_(0)cos^(2)((pi x)/(beta))`

D

`(I_(0))/(4)cos^(2)((pi x)/(beta))`

Text Solution

Verified by Experts

The correct Answer is:
C
`I=I_(0)cos^(2)((theta)/(2)), theta = (2pi)/(lambda)x`
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NARAYNA-WAVE OPTICS-LEVEL - II (C.W)
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