In a Young's double slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case

Options

A. there shall be alternate interference patterns of red and blue.
B. three shall be an interference patterns for red distinct from that for blue.
C. there shall be no interference fringes.
D. there shall be an interference pattern for red mixing with one for blue.

Explanation

To solve the problem regarding the Young's double slit experiment with a white light source, where one slit is covered with a red filter and the other with a blue filter, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Setup**:
- In a Young's double slit experiment, light from a coherent source passes through two slits, creating an interference pattern on a screen.
- Here, we have a white light source, which contains multiple wavelengths (colors).

2. **Applying Filters**:
- One slit is covered with a red filter, allowing only red light to pass through.
- The other slit is covered with a blue filter, allowing only blue light to pass through.

3. **Analyzing the Light**:
- The light coming from the first slit is monochromatic red light.
- The light coming from the second slit is monochromatic blue light.
- Since the two slits are illuminated by different colors of light, the light waves are not of the same wavelength.

4. **Condition for Interference**:
- For interference to occur, the light waves from both slits must be coherent and monochromatic (i.e., of the same wavelength).
- In this case, the red and blue lights are not coherent with each other because they have different wavelengths.

5. **Conclusion**:
- Since the condition for interference (monochromatic light from both slits) is not satisfied, no interference pattern will form on the screen.
- Therefore, there will be no interference fringes observed.

### Final Answer:
There will be no interference fringes due to the use of different colors of light from the two slits.

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