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Consider the diffraction patern for a sm...

Consider the diffraction patern for a small pinhole. As the size of the hole is increased

A

the size decreases.

B

the intensity increases

C

the size increases

D

the intensity decreases.

Text Solution

Verified by Experts

The correct Answer is:
A, B
`beta = 2lambda (D)/(d)` is the width of primary maximum in difraction pattern. Intensity `I = I_(0) ((sin alpha)/(alpha))^(2)` where `alpha = (pi d)/(lambda) sin theta`
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