Statement - I : Reflection results in plane front the side with higher refractive index.
Statement - II : Brewster's angle is less than critical angle.

Options

A. Statement-I is true and Statement-II is true and Statement-II is the correct explanation of Statement-I.
B. Statement-I asnd Statement-II are true but Statement-II is not the correct explanation of Statement-I
C. Statement-I is true, Statement-II is false
D. Statement-I is false, Statement-II is true.

Answer

A

Explanation

Brewster's angle i.e. `tan theta_(B) = (n_(2))/(n_(1))` where `n_(2) lt n_(1)` .
critical angle is `sin theta_(c ) = (n_(2))/(n_(1))`
where `n_(2) lt n_(1)` .
As `|tan theta_(B)|gt|sin theta_(c )|` for , arge amgles, `theta_(B) lt theta_(C )` . Thus, polarisation by reflection shall definetly occure.