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For the equilibrium equation 2NH3(g)hA...

For the equilibrium equation
`2NH_3(g)hArrN_2(g)+3H_2(g)`
the units of `K_p` will be

A

`(atm)^(-2)`

B

`(atm)^2`

C

`(atm)^3`

D

`atm`

Text Solution

Verified by Experts

The correct Answer is:
B
According to the law of chemical equilibrium,
`K_p=(P_(N_2)P_(H_2)^3)/(P_(NH_3)^2)`
Expressing pressure in atmosphere, we have
`K_p=((atm)^4)/((atm)^2)=(atm)^2`
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