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1.7g of NH3(g) is present in a 2-L flask...

`1.7g` of `NH_3(g)` is present in a `2-L` flask. The active mass of `NH_3(g)` is

A

`0.1M`

B

`0.02M`

C

`0.05M`

D

`0.5M`

Text Solution

Verified by Experts

The correct Answer is:
C

For gaseous substances, active mass can be expressed in terms of molar concentration (molarity):
`M=(n_(NH_3))/(V_L)=(1.7g//17gmol^(-1))/(2L)`
`=0.05M`
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