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The equilibrium constant Kp for the reac...

The equilibrium constant `K_p` for the reaction
`AhArr2B`
is related to the degree of dissociation `(alpha)` of A and total pressure `P` as

A

`(4alpha^2P)/(1-alpha)`

B

`(4alpha^2P^2)/(1-alpha)`

C

`(4alpha^2P)/(1-alpha^2)`

D

`(4alpha^2P^2)/(1-alpha^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,A hArr 2B),("Initial moles","1 0"),("Change",-alpha+2alpha),("Equilibrium moles",bar(1-alpha " 2"alpha)):}`
Partial pressure =(Mole fraction)(Total pressure)
Mole fraction = Moles/Total moles
`n_A=1-alpha`, `n_B=2alpha`, and `n_t=(1-alpha)+(2alpha)=1+alpha`
`:. P_A=((1-alpha)/(1+alpha))P`, `P_B=((2alpha)/(1+alpha))P`
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