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The equilibrium for the formation of SO3...

The equilibrium for the formation of `SO_3` was established at a certain temperature starting with one mole of `O_2` and two moles of `SO_2`. If `V` is the volume of the vessel and `2x` is the number of moles of `SO_3` present at equilbrium, then equilibrium constant will be

A

`((1-x)^3)/(2V)`

B

`(4x^2)/((2-x)(1-x))`

C

`(x^2)/((2-x)(1-x))`

D

`(x^2V)/((1-x)^3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)),("Initial moles"," 2 1 0"),("Change"," -2x -x +2x"),("Equilibrium moles",bar(" (2-2x) (1-x) 2x ")),("Equilibrium concentration",(2(1-x))/(V)" "((1-x))/(V)" "(2x)/(V)):}`
`K_c=(C_(SO_3)^2)/(C_(SO_2)^2CO_2)`
`=(((2x)/(V))^2)/([(2(-x))/(V)]^2((1-x))/(V))`
`=(4x^2//V^2)/((4(1-x)^2)/(V^2)((1-x))/(V))=(x^2V)/((1-x)^3)`
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