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If the concentration of the weak monopr...

If the concentration of the weak monoprotic acid HA is C mmol `L^(-1)` and its ionization constant is `K_(a)`, then

A

`C_(H)^(+)=C//2`

B

`C_(H)^(+)=sqrt(C )`

C

`C_(H)^(+)=sqrt(K_(a)C)`

D

`C_(H)^(+)=C//C_(a)`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,HA(aq.),hArrH^(+)(aq.),+A^(-)(aq.)),("Inital (M)",C,0,0),("Change (M)",C-Calpha,Calpha,Calpha),("Equilibrium (M)",C-Calpha,Calpha,Calpha):}`
where `alpha` is the degree of ionization.
`K_(a)=(C_(H^(+))C_(A^(-)))/(C_(HA))`
`=((Calpha)(Calpha))/(C(1-alpha))`
`=Calpha^(2)` because `alpha lt lt 1`
or `alpha=sqrt((K_(a))/(C ))`
`C_(H^(+))=Calpha=Csqrt((K_(a))/(C ))=sqrt(K_(a)C )`
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